Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Η | 28918 | 1750 | 10 | 175.0000 |
Ο | 24173 | 1550 | 11 | 140.9091 |
Το | 17437 | 1019 | 10 | 101.9000 |
οποίος | 3076 | 193 | 2 | 96.5000 |
Οι | 12720 | 766 | 8 | 95.7500 |
οποία | 6448 | 324 | 5 | 64.8000 |
Όπως | 2815 | 124 | 2 | 62.0000 |
Στο | 4822 | 297 | 5 | 59.4000 |
Και | 5364 | 160 | 3 | 53.3333 |
οποίοι | 1144 | 50 | 1 | 50.0000 |
Τα | 5065 | 319 | 7 | 45.5714 |
Στην | 3542 | 223 | 5 | 44.6000 |
οποίο | 4149 | 219 | 5 | 43.8000 |
Στις | 1337 | 125 | 3 | 41.6667 |
Σε | 4707 | 208 | 6 | 34.6667 |
Την | 3479 | 168 | 5 | 33.6000 |
Είναι | 4398 | 185 | 6 | 30.8333 |
Με | 5304 | 175 | 6 | 29.1667 |
οποίων | 773 | 28 | 1 | 28.0000 |
Δεν | 6640 | 213 | 9 | 23.6667 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
εκατ | 2034 | 2 | 141 | 0.0142 |
δισ | 1111 | 2 | 83 | 0.0241 |
μπορείτε | 301 | 1 | 17 | 0.0588 |
Αγ | 173 | 1 | 11 | 0.0909 |
Ηλιακό | 58 | 1 | 11 | 0.0909 |
Φώφη | 171 | 1 | 10 | 0.1000 |
Wall | 84 | 1 | 10 | 0.1000 |
όλων | 1062 | 7 | 68 | 0.1029 |
μπορείς | 662 | 3 | 28 | 0.1071 |
έπειτα | 714 | 1 | 9 | 0.1111 |
Champions | 503 | 1 | 9 | 0.1111 |
ενδέχεται | 197 | 1 | 9 | 0.1111 |
καιρικές | 94 | 1 | 9 | 0.1111 |
αντιμέτωπος | 72 | 1 | 9 | 0.1111 |
αναμένεται | 1776 | 11 | 98 | 0.1122 |
μετά | 8557 | 22 | 185 | 0.1189 |
αυτής | 763 | 6 | 48 | 0.1250 |
λίγους | 165 | 1 | 8 | 0.1250 |
προσπάθησαν | 161 | 1 | 8 | 0.1250 |
Ζόραν | 83 | 1 | 8 | 0.1250 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II